Dear Aspirants , This is the third set of problems for JEE Mains 2013. The level is Advance, questions may be tough for some students. Have patience and be committed towards your goal. Try to solve it completely for better revision of concepts before exam. I wish you all the best for exam on Sunday. I'll be releasing "detailed solutions of JEE Mains" paper on Sunday just after exam, so be in regular touch with updates of this blog. Best of luck... Hridesh :) Problem Set 3 JEE Mains 2013 Page 1 Problem Set 3 JEE Mains 2013 Page 2 Problem Set 3 JEE Mains 2013 Page 3 Problem Set 3 JEE Mains 2013 Page 4 Problem Set 3 JEE Mains 2013 Page 5 Problem Set 3 JEE Mains 2013 Page 6 Problem Set 3 JEE Mains 2013 Page 7 Problem Set 3 JEE Mains 2013 Page 8 Problem Set 3 JEE Mains 2013 with Answer Key Page 9
thank u sir . wonderful work!!!! it is really helpful.please explain ques no. 31
ReplyDeletethanks
regards
Thanks Princy for your comments... In Q 31 the first step is Dehydrohalogentaion process lead to the formation of ethene, then Bromine will add up on ethene by halogenation process and after all in last step bromine will be replaced by CN via SN2 reaction leads to formation of the product (B)
Deleteques no. 29 why b option is not correct?
ReplyDeleteI've updated the set which will solve all your doubts... have a look on updated version.... thanks in advance and sorry for the inconvenience caused..
DeleteHridesh :)
explain ques no. 27
ReplyDeletethis is the order of bond energy of halides as well as their dipole moment...
Deleteques 17th
ReplyDeletelower the reduction electrode potential higher will be the reducing power... see electrochemical series for more details..
Deleteplease help me with ques no. 2
ReplyDeletemaximum Ba2+ available is 0.5 M(Limiting Reactant) hence the maximum amount of BaSO4 possible is 0.5 moles... its simple. :)
Deletewhat is the answer of ques no. 11 is it A ?THERE IS MISPRINTING IN ANSWER SHEET.
ReplyDeleteyes, its answer is A... it was a misprint which has been updated... have a look :)
Deletesir please tell me what is walden inversion and when does it take place???
ReplyDeleteWalden inversion is stereo chemical inversion of product relative to reactant stereo configuration means if reactant is chiral and d/l form than the product will be l/d (Invered)form... It is the characteristic property shown in SN2 reactions. :)
Delete