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Advance Problem Set 3 for JEE Mains 2013

Dear Aspirants,

This is the third set of problems for JEE Mains 2013. The level is Advance, questions may be tough for some students. Have patience and be committed towards your goal.

 Try to solve it completely for better revision of concepts before exam. I wish you all the best for exam on Sunday.

 I'll be releasing "detailed solutions of JEE Mains" paper on Sunday just after exam, so be in regular touch with updates of this blog.

Best of luck...

Hridesh :)

Problem Set 3 JEE Mains 2013 Page 1
Problem Set 3 JEE Mains 2013 Page 2
Problem Set 3 JEE Mains 2013 Page 3
Problem Set 3 JEE Mains 2013 Page 4
Problem Set 3 JEE Mains 2013 Page 5
Problem Set 3 JEE Mains 2013 Page 6
Problem Set 3 JEE Mains 2013 Page 7
Problem Set 3 JEE Mains 2013 Page 8
Problem Set 3 JEE Mains 2013 with Answer Key Page 9




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Comments

  1. Unknown9 April 2013 at 17:30

    can u please help me with question no. 12?
    your website is very nice ....]
    the level of organic chemistry questions is bit difficult....
    your help is a must....

    ReplyDelete
    Replies
    1. Hridesh Kumar Shrotriya9 April 2013 at 23:34

      thanks tanaz for your appreciation.... in Q 12 the first step leading to P is E1 reaction which lead us to product mentioned in option(C)which in turn isomerises to option (B) as it is aromatic and much more stable :)

      Delete
  2. Unknown9 April 2013 at 17:43

    may i post the answers of organic chemistry question will u verify they are correct or not .because we reach correct answers but we may be conceptuallty wrong and it will help others also

    ReplyDelete
    Replies
    1. Hridesh Kumar Shrotriya9 April 2013 at 23:35

      yes you are most welcome... I'd appreciate that and will let you know asap in case of conceptual error :)

      Delete
  3. Unknown9 April 2013 at 18:17

    sir i am struck on question no. 27

    ReplyDelete
    Replies
    1. Hridesh Kumar Shrotriya9 April 2013 at 23:37

      The unexpected product will be by bimolecular reduction(Free radical based)followed by rearrangement leading to the product given in answer... give it a try once again...

      Delete
    2. Unknown10 April 2013 at 07:08

      i did not get u sir

      Delete
    3. Unknown10 April 2013 at 08:26

      i searched the entire web and referred the ques to my chemistry teacher she did not get the question only??/

      Delete
    4. Unknown10 April 2013 at 08:54

      i referred nptel programme

      Delete
    5. Unknown10 April 2013 at 08:55

      no answer there also sir

      Delete
    6. punita11 April 2013 at 07:45

      sir waiting for answer and explanation and mechanism q no. 27

      Delete
    7. Hridesh Kumar Shrotriya11 April 2013 at 08:24

      @all- as the compound is having 2 carbonyl group the metal will provide 1 electron each to both of them and a pinacol will be formed first which will rearrange to a pinacolone in presence of acid. After pinacolone's normal reduction you will get your unexpected product... If still you are not getting it than let me know...

      Delete
  4. Unknown9 April 2013 at 18:53

    question 19

    ReplyDelete
    Replies
    1. Hridesh Kumar Shrotriya9 April 2013 at 23:39

      in presence of HBF4 a carbocation Ph3C+ will be formed which will add up on Phenol via Electrophillic substitution reaction leading to the product :)

      Delete

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